Balloon Iron
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Balloon Iron

Chemistry Help?
Here's the problem:
In 1897 the Swedish explorer Andree tied to reach the North Pole in a balloon. The balloon was filled with hydrogen gas. The hydrogen gas was prepared from iron splints and diluted sulfuric acid. The reaction is:
Fe(s) + H2SO4 (aq) ----> FeSO4(aq) + H2(g)
The volume of the balloon was 4800 m^3 and the loss of hydrogen gas during filling was estimated at 20%. What mass of iron splints and 98% (by mass) H2SO4 were needed to ensure the complete filling of the balloon? Assume a temperature of 0C (273K), a pressure of 1.0 atm during filling, and 100% yield.
Steps to show this would be wonderful!
We need to calculate how many moles of H2 there are. Use the ideal gas law.
V = 4800 m^3 x (10 dm / m)^3 = 4.8 x 10^6 dm^3 = 4.8 x 10^6 L
PV = nRT
n = PV / RT = (1.0)(4.8 x 10^6) / (0.0821)(273)
= 214,000 moles H2
If you lose 20% during filling, then you really need
1.2 x 214,000 moles = 257,000 moles H2.
257,000 moles H2 x (1 mole Fe / 1 mole H2) x (55.85 g Fe / 1 mole Fe) = 1.43 x 10^7 g Fe = 14,300 kg Fe.
257,000 moles H2 x (1 mole H2SO4 / 1 mole H2) x (98.1 g H2SO4 / 1 mole H2SO4) x (100% / 98%) = 2.57 x 10^7 g H2SO4 = 25,700 kg H2SO4.
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Two Balloon Iron Man
Gas Laws interesting question but difficult. Help will be much appreciated.?
In 1897 the Swedish explorer Andree tried to reach the North Pole in a balloon. The balloon was filled with hydrogen gas. The hydrogen gas was prepared from iron splints and diluted sulfuric acid. The reaction is given below.
Fe(s) + H2SO4(aq) FeSO4(aq) + H2(g)
The volume of the balloon was 4350 m3 and the loss of hydrogen gas during filling was estimated at 20.0%. What mass (in kg) of iron splints and 86.2% (by mass) H2SO4 were needed to ensure the complete filling of the balloon? Assume a temperature of 0°C, a pressure of 1.00 atm during filling, and 100% yield.
iron splints:_________ kg
86.2% sulfuric acid: ___________kg
1mol H2 at STP ( you are happily working at STP) has a volume of 22.4 litres.
You need 4350m³ , therefore you will need:
4350000/22.4 = 194,196.4mol H2
But you lost 20% of the gas, therefore you will need to produce:
Mol of H2 = 100/80*194,196 = 242,746mol H2
From the balanced equation:
1mol Fe will produce 1mol H2
You require 242,746 mol Fe
Molar mass Fe = 55.847g/mol
Mass of Fe required: 242,746*55.847 = 13,556,610g Fe
You require 13,557 kg of Fe
Similarly, from the balanced equation:
1mol H2SO4 will produce 1mol H2
You require 242,746 mol H2SO4
Molar mass H2SO4 = 98.0791 g/mol
242,746mol = 242,746*98.0791 = 23,808,309g H2SO4 100%
But your acid is 86.2% : you then need
23,808,309*100/86.2 = 27,619,848g
You require: 27,620kg H2SO4 solution.


































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Balloon men RT When I'm not on Twitter I'm still pumping iron
lol – awesome tutorial! I think you're my new favorite balloon person! keep up the good work!